If $A = \{ x : x \text{ is an integer and } x^2 - 9 = 0 \}$,$B = \{ x : x \text{ is a natural number and } 2 \leq x < 5 \}$,and $C = \{ x : x \text{ is a prime number } \leq 4 \}$,then $(B - C) \cup A$ is:
- A$\{ -3, 3, 4 \}$
- B$\{ 2, 3, 4 \}$
- C$\{ 3, 4, 5 \}$
- D$\{ 2, 3, 5 \}$
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