If tan A + cot A = 2,then the value of tan^{4 | vedclass

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(A) Given,$	an A + \cot A = 2$. Squaring both sides,we get: $(	an A + \cot A)^{2} = 2^{2}$ $	an^{2} A + \cot^{2} A + 2 	an A \cot A = 4$ Since $

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$2$

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(A) Given,$	an A + \cot A = 2$. Squaring both sides,we get: $(	an A + \cot A)^{2} = 2^{2}$ $	an^{2} A + \cot^{2} A + 2 	an A \cot A = 4$ Since $	an A \cot A = 1$,we have: $	an^{2} A + \cot^{2} A + 2 = 4$ $	an^{2} A + \cot^{2} A = 2$ Now,squaring both sides again: $(	an^{2} A + \cot^{2} A)^{2} = 2^{2}$ $	an^{4} A + \cot^{4} A + 2 	an^{2} A \cot^{2} A = 4$ $	an^{4} A + \cot^{4} A + 2(1)^{2} = 4$ $	an^{4} A + \cot^{4} A = 4 - 2 = 2$.

If $\tan A + \cot A = 2$,then the value of $\tan^{4} A + \cot^{4} A$ is:

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