(A) Given the inequality $|3x - 5| \leq 2$. By the property of absolute value inequalities,$|f(x)| \leq a \iff -a \leq f(x) \leq a$. Therefore,$-2 \le

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(A) Given the inequality $|3x - 5| \leq 2$. By the property of absolute value inequalities,$|f(x)| \leq a \iff -a \leq f(x) \leq a$. Therefore,$-2 \leq 3x - 5 \leq 2$. Adding $5$ to all parts of the inequality: $-2 + 5 \leq 3x \leq 2 + 5$ $3 \leq 3x \leq 7$. Dividing by $3$: $1 \leq x \leq \frac{7}{3}$.