If $A$ and $B$ are mutually exclusive events,$P(A) = \frac{1}{2}$,$P(A \cup B) = \frac{3}{5}$,and $P(B') = p$,then $p = $ . . . . . . .
- A$\frac{1}{5}$
- B$\frac{2}{5}$
- C$\frac{9}{10}$
- D$\frac{1}{10}$
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