One of the two events must occur. If the chance of one is $\frac{2}{3}$ of the other,then the odds in favour of the other are

If $A$ and $B$ are two independent events,then $P(A \cup B) = $

Statement $- I :$ If the probabilities of solving a problem by $A$ and $B$ are $1/3$ and $1/4$ respectively,then the probability that the problem is solved is $7/12$.
Statement $- II :$ The events described above are independent events.

Three critics review a book. For the three critics,the odds in favour of the book are $2:5$,$3:4$,and $4:3$ respectively. The probability that the majority is in favour of the book is given by

Two dice are thrown simultaneously. The probability that the sum is odd or less than $7$ or both is:

$A, B, C$ are three events,one of which must and only one can happen. The odds in favour of $A$ are $4:6$,and the odds against $B$ are $7:3$. Then,the odds against $C$ are: