If sec theta + tan theta = p, then tan theta | vedclass

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Question

(b) $\sec 	heta + 	an 	heta = p\,\, $........$(i)$

$\Rightarrow \,\sec \,	heta - 	an 	heta = \frac{1}{p}$..........$(ii)$

Subtracting seco

Vedclass · Accepted Answer

$\frac{{{p^2} - 1}}{{2p}}$

Vedclass · Answer

(b) $\sec 	heta + 	an 	heta = p\,\, $........$(i)$

$\Rightarrow \,\sec \,	heta - 	an 	heta = \frac{1}{p}$..........$(ii)$

Subtracting second from first, we get

$2	an 	heta = p - \frac{1}{p}$

$ \Rightarrow \,	an 	heta = \frac{{{p^2} - 1}}{{2p}}$.

If $\sec \theta + \tan \theta = p,$ then $\tan \theta $ is equal to

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