If sin x = frac{{ - 24}}{{25}}, then the valu | vedclass

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Question

(b) $\cos x = \sqrt {1 - {{\sin }^2}x} $

$= \sqrt {1 - {{\left( {\frac{{ - 24}}{{25}}} ight)}^2}} = \frac{7}{{25}}$

$ \Rightarrow 	an x = \fr

Vedclass · Accepted Answer

$\frac{{ - 24}}{7}$

Vedclass · Answer

(b) $\cos x = \sqrt {1 - {{\sin }^2}x} $

$= \sqrt {1 - {{\left( {\frac{{ - 24}}{{25}}} ight)}^2}} = \frac{7}{{25}}$

$ \Rightarrow 	an x = \frac{{\sin x}}{{\cos x}} = \frac{{ - 24}}{7}$.

If $\sin x = \frac{{ - 24}}{{25}},$ then the value of $\tan \, x$ is

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