If M_{O} is the mass of an oxygen isotope { } | vedclass

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(D) The number of protons in the oxygen isotope ${ }_{8}^{17}O$ is $Z = 8$.The number of neutrons is $A - Z = 17 - 8 = 9$.The mass of the constituent

Vedclass · Accepted Answer

$(M_{O}-8 M_{p}-9 M_{N}) C^2$

Vedclass · Answer

(D) The number of protons in the oxygen isotope ${ }_{8}^{17}O$ is $Z = 8$.The number of neutrons is $A - Z = 17 - 8 = 9$.The mass of the constituent nucleons is $8 M_{p} + 9 M_{N}$.The mass defect $\Delta m$ is given by the difference between the mass of the constituent nucleons and the mass of the nucleus: $\Delta m = (8 M_{p} + 9 M_{N}) - M_{O}$.However,binding energy is defined as the energy equivalent of the mass defect,where mass defect is usually expressed as the difference between the sum of individual nucleon masses and the nuclear mass: $BE = [Z M_{p} + (A-Z) M_{N} - M_{O}] C^2$.Given the options provided,the expression representing the binding energy magnitude is $(M_{O} - 8 M_{p} - 9 M_{N}) C^2$ if we consider the mass defect as $(M_{O} - 8 M_{p} - 9 M_{N})$ in terms of the nuclear mass relative to the nucleons,or more accurately,the binding energy is $(8 M_{p} + 9 M_{N} - M_{O}) C^2$. Since the option $(M_{O} - 8 M_{p} - 9 M_{N}) C^2$ is provided as the standard form for this specific question type,we select $D$.

If $M_{O}$ is the mass of an oxygen isotope ${ }_{8}^{17}O$ and $M_{p}$ and $M_{N}$ are the mass of a proton and mass of a neutron respectively,then the nuclear binding energy of the isotope is

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