Assuming the experimental mass of ^{12}_{6}C | vedclass

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(B) The nucleus of $^{12}_{6}C$ contains $6$ protons and $6$ neutrons.The mass of the constituent nucleons is calculated as:$M_{nucleons} = 6 	imes m

Vedclass · Accepted Answer

$0.09558$

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(B) The nucleus of $^{12}_{6}C$ contains $6$ protons and $6$ neutrons.The mass of the constituent nucleons is calculated as:$M_{nucleons} = 6 	imes m_p + 6 	imes m_n$$M_{nucleons} = 6 	imes 1.00727 	ext{ u} + 6 	imes 1.00866 	ext{ u}$$M_{nucleons} = 6.04362 	ext{ u} + 6.05196 	ext{ u} = 12.09558 	ext{ u}$.The mass defect $\Delta m$ is the difference between the sum of the masses of the nucleons and the actual mass of the nucleus:$\Delta m = M_{nucleons} - M_{nucleus}$$\Delta m = 12.09558 	ext{ u} - 12.00000 	ext{ u} = 0.09558 	ext{ u}$.

Assuming the experimental mass of $^{12}_{6}C$ as $12 \text{ u}$,the mass defect of $^{12}_{6}C$ atom is . . . . . . $\text{u}$. (Mass of proton $= 1.00727 \text{ u}$,mass of neutron $= 1.00866 \text{ u}$).

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