If A = begin{bmatrix} 3 & 1 -1 & 2 end{bmatr | vedclass

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(D) Given $A = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$.To find ${A^2}$,we perform matrix multiplication $A 	imes A$:${A^2} = \begin{bmatrix} 3

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$\begin{bmatrix} 8 & 5 \ -5 & 3 \end{bmatrix}$

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(D) Given $A = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$.To find ${A^2}$,we perform matrix multiplication $A 	imes A$:${A^2} = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix} \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$Calculating the elements:Row $1$,Column $1$: $(3 	imes 3) + (1 	imes -1) = 9 - 1 = 8$Row $1$,Column $2$: $(3 	imes 1) + (1 	imes 2) = 3 + 2 = 5$Row $2$,Column $1$: $(-1 	imes 3) + (2 	imes -1) = -3 - 2 = -5$Row $2$,Column $2$: $(-1 	imes 1) + (2 	imes 2) = -1 + 4 = 3$Thus,${A^2} = \begin{bmatrix} 8 & 5 \ -5 & 3 \end{bmatrix}$.

If $A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}$,then ${A^2} = $

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