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(A) Given sets are $A = \{x, y, z\}$ and $B = \{1, 2\}$.Number of elements in $A$ is $n(A) = 3$.Number of elements in $B$ is $n(B) = 2$.The Cartesian

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$64$

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(A) Given sets are $A = \{x, y, z\}$ and $B = \{1, 2\}$.Number of elements in $A$ is $n(A) = 3$.Number of elements in $B$ is $n(B) = 2$.The Cartesian product $A 	imes B$ contains $n(A) 	imes n(B) = 3 	imes 2 = 6$ elements.$A$ relation from $A$ to $B$ is a subset of $A 	imes B$.The total number of subsets of a set with $n$ elements is $2^n$.Therefore,the total number of relations from $A$ to $B$ is $2^6 = 64$.

If $A = \{x, y, z\}$ and $B = \{1, 2\}$,then the total number of relations from set $A$ to set $B$ is:

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