If (sim p wedge q) rightarrow r is false,then | vedclass

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Question

(A) The implication $A \rightarrow B$ is false only when $A$ is true and $B$ is false. Given $(\sim p \wedge q) \rightarrow r$ is false,we must have $

Vedclass · Accepted Answer

$F, T, F$

Vedclass · Answer

(A) The implication $A \rightarrow B$ is false only when $A$ is true and $B$ is false. Given $(\sim p \wedge q) \rightarrow r$ is false,we must have $(\sim p \wedge q) = T$ and $r = F$. The conjunction $A \wedge B$ is true only when both $A$ and $B$ are true. Therefore,$\sim p = T$ and $q = T$. If $\sim p = T$,then $p = F$. Thus,the truth values are $p = F, q = T, r = F$.

If $(\sim p \wedge q) \rightarrow r$ is false,then the truth values of $p, q, r$ are respectively:

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