यदि $\sin \left(\sin ^{-1} \frac{1}{5}+\cos ^{-1} x\right)=1$ है,तो $x$ का मान है

  • A
    $\frac{1}{5}$
  • B
    $1$
  • C
    $0$
  • D
    $-\frac{1}{5}$

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$\sin \left\{ {{\tan }^{ - 1}}\left( {\frac{{1 - {x^2}}}{{2x}}} \right) + {{\cos }^{ - 1}}\left( {\frac{{1 - {x^2}}}{{1 + {x^2}}}} \right) \right\}$ का मान ज्ञात कीजिए।

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