If a, b, c are in G.P.,then the equations ax^ | vedclass

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(A) Since $a, b, c$ are in $G.P.$,we have $b^2 = ac$.The equation $ax^2 + 2bx + c = 0$ becomes $ax^2 + 2\sqrt{ac}x + c = 0$.This can be written as $(\

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$A.P.$

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(A) Since $a, b, c$ are in $G.P.$,we have $b^2 = ac$.The equation $ax^2 + 2bx + c = 0$ becomes $ax^2 + 2\sqrt{ac}x + c = 0$.This can be written as $(\sqrt{a}x + \sqrt{c})^2 = 0$,which gives the repeated root $x = -\sqrt{\frac{c}{a}}$.Since this is a common root,it must satisfy $dx^2 + 2ex + f = 0$.Substituting $x = -\sqrt{\frac{c}{a}}$,we get $d(\frac{c}{a}) - 2e\sqrt{\frac{c}{a}} + f = 0$.Dividing by $c$,we get $\frac{d}{a} - 2e\frac{1}{\sqrt{ac}} + \frac{f}{c} = 0$.Since $b = \sqrt{ac}$,this becomes $\frac{d}{a} + \frac{f}{c} = \frac{2e}{b}$.This condition implies that $\frac{d}{a}, \frac{e}{b}, \frac{f}{c}$ are in $A.P.$

If $a, b, c$ are in $G.P.$,then the equations $ax^2 + 2bx + c = 0$ and $dx^2 + 2ex + f = 0$ have a common root if $\frac{d}{a}, \frac{e}{b}, \frac{f}{c}$ are in

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