If z = frac{{ - 2}}{{1 + sqrt 3 ,i}} then the | vedclass

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Question

(c)$z = \frac{{ - 2}}{{1 + \sqrt 3 i}}$=$\frac{{ - 2}}{{1 + \sqrt 3 i}} 	imes \frac{{1 - \sqrt 3 i}}{{1 - \sqrt 3 i}}$$ = \frac{{ - 2 + 2\sqrt 3 i}}{

Vedclass · Accepted Answer

$2\pi /3$

Vedclass · Answer

(c)$z = \frac{{ - 2}}{{1 + \sqrt 3 i}}$=$\frac{{ - 2}}{{1 + \sqrt 3 i}} 	imes \frac{{1 - \sqrt 3 i}}{{1 - \sqrt 3 i}}$$ = \frac{{ - 2 + 2\sqrt 3 i}}{{1 + 3}}$
$ \Rightarrow z = \frac{{ - 1}}{2} + \frac{{\sqrt 3 }}{2}i$

$ \Rightarrow \,arg\,(z) = {	an ^{ - 1}}\left( { - \frac{{\sqrt 3 /2}}{{1/2}}} ight) = \frac{{2\pi }}{3}$.

If $z = \frac{{ - 2}}{{1 + \sqrt 3 \,i}}$ then the value of $arg\,(z)$ is

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