If {i^2} = - 1, then sum i + {i^2} + {i^3} + | vedclass

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(d) $i + {i^2} + {i^3} + .......$up to $1000$ terms
$ = \frac{{i(1 - {i^{1000}})}}{{1 - i}} = $$\frac{{i(1 - {{({i^4})}^{250}})}}{{1 - i}}$$ = \frac{

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(d) $i + {i^2} + {i^3} + .......$up to $1000$ terms
$ = \frac{{i(1 - {i^{1000}})}}{{1 - i}} = $$\frac{{i(1 - {{({i^4})}^{250}})}}{{1 - i}}$$ = \frac{{i(1 - 1)}}{{1 - i}} = 0$.

If ${i^2} = - 1$, then sum $i + {i^2} + {i^3} + ...$to $1000$ terms is equal to

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