If x, y are real numbers such that 3^{(x/y)+1 | vedclass

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(D) Given the equation: $3^{(x/y)+1} - 3^{(x/y)-1} = 24$Let $u = x/y$. Then the equation becomes $3^{u+1} - 3^{u-1} = 24$.Factor out $3^{u-1}$:$3^{u-1

Vedclass · Accepted Answer

$3$

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(D) Given the equation: $3^{(x/y)+1} - 3^{(x/y)-1} = 24$Let $u = x/y$. Then the equation becomes $3^{u+1} - 3^{u-1} = 24$.Factor out $3^{u-1}$:$3^{u-1} \cdot (3^2 - 1) = 24$$3^{u-1} \cdot (9 - 1) = 24$$3^{u-1} \cdot 8 = 24$$3^{u-1} = 3$Since $3^{u-1} = 3^1$,we have $u - 1 = 1$,which implies $u = 2$.Thus,$x/y = 2$.We need to find the value of $\frac{x+y}{x-y}$. Dividing the numerator and denominator by $y$:$\frac{x/y + 1}{x/y - 1} = \frac{2 + 1}{2 - 1} = \frac{3}{1} = 3$.

If $x, y$ are real numbers such that $3^{(x/y)+1} - 3^{(x/y)-1} = 24$,then the value of $(x+y)/(x-y)$ is

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