If $a, b, c$ are real numbers such that $a+b+c=0$ and $a^2+b^2+c^2=1$, then $(3 a+5 b-8 c)^2+(-8 a+3 b+5 c)^2$ $+(5 a-8 b+3 c)^2$ is equal to

  • [KVPY 2017]
  • A

    $49$

  • B

    $98$

  • C

    $147$

  • D

    $294$

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