If ${q}_{{f}}$ is the free charge on the capacitor plates and ${q}_{{b}}$ is the bound charge on the dielectric slab of dielectric constant $k$ placed between the capacitor plates, then bound charge $q_{b}$ can be expressed as
If ${q}_{{f}}$ is the free charge on the capacitor plates and ${q}_{{b}}$ is the bound charge on the dielectric slab of dielectric constant $k$ placed between the capacitor plates, then bound charge $q_{b}$ can be expressed as
- [JEE MAIN 2021]
- A
${q}_{{b}}={q}_{{f}}\left(1-\frac{1}{{k}}\right)$
- B
${q}_{{b}}={q}_{{f}}\left(1-\frac{1}{\sqrt{{k}}}\right)$
- C
${q}_{{b}}={q}_{{f}}\left(1+\frac{1}{\sqrt{{k}}}\right)$
- D
${q}_{{b}}={q}_{{f}}\left(1+\frac{1}{{k}}\right)$
Similar Questions
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- [JEE MAIN 2021]