If $\sec 4A = \operatorname{cosec}(A - 20^\circ)$,where $4A$ is an acute angle,then the value of $A$ is $\ldots \ldots \ldots \ldots .$ (in $^\circ$)
- A$45$
- B$70$
- C$30$
- D$22$
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$\sin^{2} 60^{\circ} - \tan 45^{\circ} + \cos^{2} 30^{\circ} - \cot 90^{\circ} = \ldots$
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Part $I$ Part $II$ $1.$ $\cos(90^\circ - \theta)$ $a.$ $\sec \theta$ $2.$ $\cot(90^\circ - \theta)$ $b.$ $\sin \theta$ $3.$ $\operatorname{cosec}(90^\circ - \theta)$ $c.$ $1$ $d.$ $\tan \theta$
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| $2.$ $\cot(90^\circ - \theta)$ | $b.$ $\sin \theta$ |
| $3.$ $\operatorname{cosec}(90^\circ - \theta)$ | $c.$ $1$ |
| $d.$ $\tan \theta$ |
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View SolutionIf $\cos \theta = \frac{1}{\sqrt{2}},$ then $\theta = \ldots$ (in $^\circ$)
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