If $\cos \theta = \frac{1}{\sqrt{2}},$ then $\theta = \ldots$ (in $^\circ$)

  • A
    $30$
  • B
    $45$
  • C
    $60$
  • D
    $90$

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Similar Questions

If $\sin \theta - \cos \theta = 0$,then the value of $(\sin^4 \theta + \cos^4 \theta)$ is

Prove that,
$\frac{\tan A}{1+\sec A} + \frac{\tan A}{\sec A-1} = 2 \operatorname{cosec} A$

$2A$ is the measure of an acute angle and $\sec 2A = \operatorname{cosec}(A - 42^\circ)$,then the value of $A$ is $\ldots \ldots \ldots \ldots$ (in $^\circ$)

Write 'True' or 'False' and justify your answer.
The value of $\sin \theta + \cos \theta$ is always greater than $1$.

$2 \sin ^{2} 30^{\circ} \cot 30^{\circ}-3 \cos ^{2} 60^{\circ} \sec ^{2} 30^{\circ} = \dots$

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