If $\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}}=a+b \sqrt{30},$ find the value of $a$ and $b$.

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$\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}}=a+b \sqrt{30}$

$\therefore \frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}} \times \frac{3 \sqrt{5}+2 \sqrt{6}}{3 \sqrt{5}+2 \sqrt{6}}=a+b \sqrt{30}$

$\therefore \frac{(2 \sqrt{6}-\sqrt{5})(3 \sqrt{5}+2 \sqrt{6})}{(3 \sqrt{5})^{2}-(2 \sqrt{6})^{2}}=a+b \sqrt{30}$

$\therefore \frac{6 \sqrt{30}+24-15-2 \sqrt{30}}{45-24}=a+b \sqrt{30}$

$\therefore \frac{9+4 \sqrt{30}}{21}=a+b \sqrt{30}$

$\therefore \frac{9}{21}+\frac{4 \sqrt{30}}{21}=a+b \sqrt{30}$

$\therefore \frac{3}{7}+\frac{4 \sqrt{30}}{21}=a+b \sqrt{30}$

Equating the coefficients of rational and irrational parts on both sides, we get $a=\frac{3}{7}$ and $b=\frac{4}{21}$

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