If x^{2}+kx+6=(x+2)(x+3) for all x,then the v | vedclass

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(A) Given the equation: $x^{2}+kx+6=(x+2)(x+3)$.First,expand the right side of the equation:$(x+2)(x+3) = x(x+3) + 2(x+3)$$= x^{2} + 3x + 2x + 6$$= x^

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$5$

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(A) Given the equation: $x^{2}+kx+6=(x+2)(x+3)$.First,expand the right side of the equation:$(x+2)(x+3) = x(x+3) + 2(x+3)$$= x^{2} + 3x + 2x + 6$$= x^{2} + 5x + 6$.Now,compare this with the left side of the equation: $x^{2}+kx+6 = x^{2}+5x+6$.By comparing the coefficients of $x$ on both sides,we get $k = 5$.

If $x^{2}+kx+6=(x+2)(x+3)$ for all $x$,then the value of $k$ is

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