If a^{x} = b^{y},then | vedclass

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(C) Given the equation $a^{x} = b^{y}$.Taking the logarithm on both sides,we get:$\log(a^{x}) = \log(b^{y})$Using the power rule of logarithms,$\log(m

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$\frac{\log a}{\log b} = \frac{y}{x}$

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(C) Given the equation $a^{x} = b^{y}$.Taking the logarithm on both sides,we get:$\log(a^{x}) = \log(b^{y})$Using the power rule of logarithms,$\log(m^{n}) = n \log m$,we have:$x \log a = y \log b$Rearranging the terms to solve for the ratio $\frac{\log a}{\log b}$,we divide both sides by $x \log b$:$\frac{\log a}{\log b} = \frac{y}{x}$

If $a^{x} = b^{y}$,then

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