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(B) Given that $\alpha$ and $\beta$ are the roots of the quadratic equation $a x^{2}+b x+b=0$.From the properties of roots,we have the sum of roots $\

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(B) Given that $\alpha$ and $\beta$ are the roots of the quadratic equation $a x^{2}+b x+b=0$.From the properties of roots,we have the sum of roots $\alpha+\beta = -\frac{b}{a}$ and the product of roots $\alpha \beta = \frac{b}{a}$.Now,we need to evaluate the expression $\sqrt{\frac{\alpha}{\beta}}+\sqrt{\frac{\beta}{\alpha}}+\sqrt{\frac{b}{a}}$.Simplifying the first two terms: $\sqrt{\frac{\alpha}{\beta}}+\sqrt{\frac{\beta}{\alpha}} = \frac{\sqrt{\alpha}}{\sqrt{\beta}} + \frac{\sqrt{\beta}}{\sqrt{\alpha}} = \frac{(\sqrt{\alpha})^2 + (\sqrt{\beta})^2}{\sqrt{\alpha \beta}} = \frac{\alpha+\beta}{\sqrt{\alpha \beta}}$.Substituting the values of $\alpha+\beta$ and $\alpha \beta$ into the expression:$= \frac{-\frac{b}{a}}{\sqrt{\frac{b}{a}}} + \sqrt{\frac{b}{a}}$.Since $\frac{x}{\sqrt{x}} = \sqrt{x}$,we get:$= -\sqrt{\frac{b}{a}} + \sqrt{\frac{b}{a}} = 0$.

If $\alpha, \beta$ are the roots of the equation $a x^{2}+b x+b=0,$ then $\sqrt{\frac{\alpha}{\beta}}+\sqrt{\frac{\beta}{\alpha}}+\sqrt{\frac{b}{a}}=$

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