If $\alpha$ and $\beta$ are the roots of $6x^2 - 6x + 1 = 0$,then the value of $\frac{1}{2}[a + b\alpha + c\alpha^2 + d\alpha^3] + \frac{1}{2}[a + b\beta + c\beta^2 + d\beta^3]$ is

  • A
    $\frac{1}{4}(a + b + c + d)$
  • B
    $\frac{a}{1} + \frac{b}{2} + \frac{c}{3} + \frac{d}{4}$
  • C
    $\frac{a}{2} - \frac{b}{2} + \frac{c}{3} - \frac{d}{4}$
  • D
    None of these

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