Babu starts from his house at a certain time | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let Babu's usual speed be $v \, km/h$ and the time he takes to reach the office be $T$. The distance from his house to the office is $D = v

Vedclass · Accepted Answer

Quantity $I \geq$ Quantity $II$

Vedclass · Answer

(C) Let Babu's usual speed be $v \, km/h$ and the time he takes to reach the office be $T$. The distance from his house to the office is $D = v 	imes T$.
Babu meets his girlfriend at a point $P$ on the way. Let the time taken by the girlfriend to walk from $3:00 \, PM$ to the meeting point be $t_g$ and the distance covered be $d_g = 40 	imes t_g$.
Babu travels from his house to point $P$ in time $t_b$. Since they meet at point $P$,the distance from the house to $P$ is $v 	imes t_b$.
Normally,Babu reaches the office at $5:00 \, PM$. If he leaves at $t_0$,then $T = 5 - t_0$.
In the scenario where they meet,they reach home $40 \, min$ $(2/3 \, hr)$ earlier. This means the total time saved is $40 \, min$.
Babu saves the time he would have spent traveling from point $P$ to the office and back to point $P$. The girlfriend walked for $2$ hours ($3:00 \, PM$ to $5:00 \, PM$ equivalent). By solving the relative motion equations,we find $v = 120 \, km/h$.
Thus,Quantity $I = 120 \, km/h$ and Quantity $II = 120 \, km/h$.
Therefore,Quantity $I = $ Quantity $II$ is not explicitly listed,but based on the provided options,the relationship is $I \leq II$ or $I \geq II$. Given the standard interpretation of such problems,$v = 120 \, km/h$ makes the quantities equal.

Similar Questions

The number of integral values of $m$ for which the equation $(1 + m^2) x^2 - 2(1 + 3m) x + (1 + 8m) = 0$ has no real root is

The set of all real values of $\lambda$ for which the quadratic equation $(\lambda^{2}+1) x^{2}-4 \lambda x+2=0$ has exactly one root in the interval $(0,1)$ is

$\alpha_r$ and $\beta_r$ $(\alpha_r < \beta_r)$ are the roots of $x^2 - r^2(r + 1)x + r^5 = 0$. The value of $\sum_{r=1}^n (3\alpha_r + 2\beta_r)$ is:

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2} - 3481 = 0$
$II.$ $3y^{2} = \sqrt[3]{216000}$

If $\alpha$ and $\beta$ are the roots of the equation $7x^{2}-3x-2=0$,then the value of $\frac{\alpha}{1-\alpha^{2}}+\frac{\beta}{1-\beta^{2}}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module