If E.A.N. of central metal cation M^{2+} in a | vedclass

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(C) The $E.A.N.$ (Effective Atomic Number) is calculated using the formula: $E.A.N. = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number

Vedclass · Accepted Answer

$6$

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(C) The $E.A.N.$ (Effective Atomic Number) is calculated using the formula: $E.A.N. = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$.Given: $E.A.N. = 36$,$Z = 26$,and oxidation state of $M^{2+} = 2$.Let $n$ be the number of monodentate ligands,which is equal to the coordination number.Substituting the values: $36 = 26 - 2 + 2n$.$36 = 24 + 2n$.$12 = 2n$.$n = 6$.Thus,the number of monodentate ligands is $6$.

If $E.A.N.$ of central metal cation $M^{2+}$ in a non-chelating complex is $36$ and atomic number of metal $M$ is $26$,then the number of monodentate ligands in this complex are

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