The EAN of platinum in potassium hexachloropl | vedclass

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Question

(B) The formula of potassium hexachloroplatinate $(IV)$ is $K_2[PtCl_6]$.In this complex,the oxidation state of $Pt$ is $+4$.The atomic number of $Pt$

Vedclass · Accepted Answer

$86$

Vedclass · Answer

(B) The formula of potassium hexachloroplatinate $(IV)$ is $K_2[PtCl_6]$.In this complex,the oxidation state of $Pt$ is $+4$.The atomic number of $Pt$ is $78$.The coordination number is $6$,so the number of electrons donated by $6$ ligands is $6 	imes 2 = 12$.$EAN = Z - 	ext{oxidation state} + 2 	imes (	ext{coordination number})$$EAN = 78 - 4 + 12 = 86$.

The $EAN$ of platinum in potassium hexachloroplatinate $(IV)$ is :

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