What is the EAN of Co in [Co(NH_3)_6]^{3+}? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $EAN$ (Effective Atomic Number) is calculated using the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes 	ext{coordination number}$.For

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(A) The $EAN$ (Effective Atomic Number) is calculated using the formula: $EAN = Z - 	ext{oxidation state} + 2 	imes 	ext{coordination number}$.For $[Co(NH_3)_6]^{3+}$:$1$. The atomic number $(Z)$ of $Co$ is $27$.$2$. The oxidation state of $Co$ is calculated as $x + 6(0) = +3$,so $x = +3$.$3$. The coordination number is $6$ (since $NH_3$ is a monodentate ligand).$4$. $EAN = 27 - 3 + 2(6) = 24 + 12 = 36$.

What is the $EAN$ of $Co$ in $[Co(NH_3)_6]^{3+}$?

Similar Questions

What is the value of the effective atomic number $(EAN)$ of cobalt in the $[Co(NH_3)_6]^{3+}$ complex,given that the atomic number of $Co$ is $Z=27$?

What is the $EAN$ of $Fe$ in $[Fe(CN)_6]^{3-}$?

What is the Effective Atomic Number $(EAN)$ of Cobalt in $[Co(NH_3)_6]Cl_3$ (Atomic number of $Co = 27$)?

Effective Atomic Number $(EAN)$ of $Co$ in $Co_2(CO)_8$ will be

What is the oxidation state of cobalt in a coordination complex if its $EAN$ is $36$ and the value of $C.N.$ is $6$? (Given: Atomic number of cobalt = $27$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module