If ${N_x}$ is the number of bonding orbitals of an atom and ${N_y}$ is the number of antibonding orbitals, then the molecule/atom will be stable if
If ${N_x}$ is the number of bonding orbitals of an atom and ${N_y}$ is the number of antibonding orbitals, then the molecule/atom will be stable if
- A
${N_x} > {N_y}$
- B
${N_x} = {N_y}$
- C
${N_x} < {N_y}$
- D
${N_x} \le {N_y}$
Similar Questions
Among the following, the molecule expected to be stabilized by anion formation is
Among the following, the molecule expected to be stabilized by anion formation is
- [JEE MAIN 2019]
Which of the following order of bond strength is correct ?
Which of the following order of bond strength is correct ?
In which of the following process, the value of bond order & magnetic nature does not change?
In which of the following process, the value of bond order & magnetic nature does not change?
Explain in Short : $\mathrm{MO}$ occupancy and molecular properties for ${{\rm{B}}_2}{\rm{,}}{{\rm{C}}_2}{\rm{, }}{{\rm{N}}_2},{{\rm{O}}_2}{\rm{,}}{{\rm{F}}_2},{\rm{N}}{{\rm{e}}_2}$.
Explain in Short : $\mathrm{MO}$ occupancy and molecular properties for ${{\rm{B}}_2}{\rm{,}}{{\rm{C}}_2}{\rm{, }}{{\rm{N}}_2},{{\rm{O}}_2}{\rm{,}}{{\rm{F}}_2},{\rm{N}}{{\rm{e}}_2}$.
The bond order of $O_2^ + $ is the same as in
The bond order of $O_2^ + $ is the same as in