If f(a) = a^2 + a+ 1 , then number of solutio | vedclass

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Question

$f\left(a^{2}\right)-3 f(a)=0$

$\Rightarrow\left(a^{4}+a^{2}+1\right)-3\left(a^{2}+a+1\right)=0$

$\Rightarrow\left(a^{2}+a+1\right)\left(a^{2}-a

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$f\left(a^{2}\right)-3 f(a)=0$

$\Rightarrow\left(a^{4}+a^{2}+1\right)-3\left(a^{2}+a+1\right)=0$

$\Rightarrow\left(a^{2}+a+1\right)\left(a^{2}-a+1\right)-3\left(a^{2}+a+1\right)=0$

$\Rightarrow\left(a^{2}+a+1\right)\left(a^{2}-a-2\right)=0$

If $f(a) = a^2 + a+ 1$ , then number of solutions of equation $f(a^2) = 3f(a)$ is

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