Identify the wrong statement for the followin | vedclass

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Question

(B) Reaction $A$ is an electrophilic addition of $HBr$ to $3$-methyl-$1$-butene,which involves a $1,2$-hydride shift to form a more stable $3^\circ$ c

Vedclass · Accepted Answer

$A$ and $C$ both products are saturated compounds.

Vedclass · Answer

(B) Reaction $A$ is an electrophilic addition of $HBr$ to $3$-methyl-$1$-butene,which involves a $1,2$-hydride shift to form a more stable $3^\circ$ carbocation,resulting in $2$-bromo-$2$-methylbutane ($3^\circ$ halide,saturated).Reaction $B$ is a free radical addition of $HBr$ in the presence of peroxide (Anti-Markovnikov),forming $1$-bromo-$3$-methylbutane ($1^\circ$ halide,saturated).Reaction $C$ is an allylic bromination using $NBS$,which follows a free radical substitution mechanism to form $3$-bromo-$3$-methyl-$1$-butene ($3^\circ$ halide,unsaturated).Since $C$ is an unsaturated compound (contains a double bond),statement $(b)$ is incorrect.

Identify the wrong statement for the following reactions:
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr} A$
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr + ROOR} B$
$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{NBS} C$

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Identify the wrong statement for the following reactions:$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr} A$$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{HBr + ROOR} B$$CH_3-CH(CH_3)-CH=CH_2 \xrightarrow{NBS} C$