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(C) The peroxide effect (Kharasch effect) is observed only with $HBr$ due to the favorable energetics of the free radical mechanism. For $HCl$,the $H-

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Anti-Markovnikov addition only for $HBr$

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(C) The peroxide effect (Kharasch effect) is observed only with $HBr$ due to the favorable energetics of the free radical mechanism. For $HCl$,the $H-Cl$ bond is too strong to be broken by the free radical. For $HI$,the iodine radical $(I^{\bullet})$ is formed,but the $I-I$ bond is too weak,and the iodine radicals prefer to recombine to form $I_2$ rather than adding to the double bond. Therefore,only $HBr$ shows Anti-Markovnikov addition in the presence of peroxide.

What is the product obtained from the reaction of propene with $HCl$,$HBr$,and $HI$ in the presence of peroxide?

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