Identify the type of hybridization involved i | vedclass

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Question

(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is

Vedclass · Accepted Answer

$d^2sp^3$

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(B) In the hexaamminecobalt$(III)$ complex ion,$[Co(NH_3)_6]^{3+}$,the central metal ion is $Co^{3+}$.The electronic configuration of $Co$ $(Z=27)$ is $[Ar] 3d^7 4s^2$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.Since $NH_3$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals.This results in two empty $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals,which undergo $d^2sp^3$ hybridization to form an octahedral complex.

List-$I$	List-$II$
$A. Ni(CO)_4$	$I. sp^3$
$B. [Ni(CN)_4]^{2-}$	$II. sp^3d^2$
$C. [Co(CN)_6]^{3-}$	$III. d^2sp^3$
$D. [CoF_6]^{3-}$	$IV. dsp^2$

Identify the type of hybridization involved in the hexaamminecobalt$(III)$ complex ion.

Similar Questions

Which of the following complexes does not involve inner orbital hybridization?

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A. Ni(CO)_4$ $I. sp^3$

$B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$

$C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$

$D. [CoF_6]^{3-}$ $IV. dsp^2$

Choose the correct answer from the options given below.

When $(n-1)d$ orbitals participate in the hybridization of a coordination complex,the resulting complex is known as:

Aluminium chloride in acidified aqueous solution forms an ion having which geometry?

The type of hybridization involved in the metal ion of the $[Ni(H_2O)_6]^{2+}$ complex is:

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