Match List-I with List-II. List-I List | vedclass

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(B) $Ni(CO)_4$: The oxidation state of $Ni$ is $0$. The configuration is $3d^8 4s^2$. Due to the strong field ligand $CO$,electrons pair up,resulting

Vedclass · Accepted Answer

$A-I, B-IV, C-III, D-II$

Vedclass · Answer

(B) $Ni(CO)_4$: The oxidation state of $Ni$ is $0$. The configuration is $3d^8 4s^2$. Due to the strong field ligand $CO$,electrons pair up,resulting in $sp^3$ hybridization.$[Ni(CN)_4]^{2-}$: The oxidation state of $Ni$ is $+2$. The configuration is $3d^8$. Due to the strong field ligand $CN^-$,the electrons pair up,resulting in $dsp^2$ hybridization.$[Co(CN)_6]^{3-}$: The oxidation state of $Co$ is $+3$. The configuration is $3d^6$. Due to the strong field ligand $CN^-$,the electrons pair up,resulting in $d^2sp^3$ hybridization.$[CoF_6]^{3-}$: The oxidation state of $Co$ is $+3$. The configuration is $3d^6$. Due to the weak field ligand $F^-$,the electrons do not pair up,resulting in $sp^3d^2$ hybridization.Therefore,the correct matching is $A-I, B-IV, C-III, D-II$.

List-$I$	List-$II$
$A. Ni(CO)_4$	$I. sp^3$
$B. [Ni(CN)_4]^{2-}$	$II. sp^3d^2$
$C. [Co(CN)_6]^{3-}$	$III. d^2sp^3$
$D. [CoF_6]^{3-}$	$IV. dsp^2$

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A. Ni(CO)_4$ $I. sp^3$

$B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$

$C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$

$D. [CoF_6]^{3-}$ $IV. dsp^2$

Choose the correct answer from the options given below.

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Match List-$I$ with List-$II$. List-$I$ List-$II$ $A. Ni(CO)_4$ $I. sp^3$ $B. [Ni(CN)_4]^{2-}$ $II. sp^3d^2$ $C. [Co(CN)_6]^{3-}$ $III. d^2sp^3$ $D. [CoF_6]^{3-}$ $IV. dsp^2$ Choose the correct answer from the options given below.