When $(n-1)d$ orbitals participate in the hybridization of a coordination complex,the resulting complex is known as:

  • A
    High spin complex
  • B
    Low spin complex
  • C
    Zero spin complex
  • D
    Positive spin complex

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Similar Questions

Give the correct sequence of initials $T$ or $F$ for the following statements. Use $T$ if the statement is true and $F$ if it is false.
$(I) \ Co(III)$ is stabilized in the presence of weak field ligands,while $Co(II)$ is stabilized in the presence of strong field ligands.
$(II)$ Four-coordinated complexes of $Pd(II)$ and $Pt(II)$ are diamagnetic and square planar.
$(III) \ [Ni(CN)_4]^{4-}$ ion and $[Ni(CO)_4]$ are diamagnetic tetrahedral and square planar respectively.
$(IV) \ Ni^{2+}$ ion does not form inner orbital octahedral complexes.

In which of the following configurations will there be the possibility of both paramagnetism and diamagnetism,depending on the nature of the ligands?

Consider the transition metal ions $Mn^{3+}$,$Cr^{3+}$,$Fe^{3+}$,and $Co^{3+}$. All form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$-orbitals of the complexes is:

Which of the following is an outer orbital complex?

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The complex ion which has no $d$ electrons in the central metal atom is

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