Difficult
Identify the reaction intermediate of the following reaction sequence:
$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$
$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$
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Overall: $2 SO_{2(g)} + O_{2(g)} \rightarrow 2 SO_{3(g)}$
$(i)$ $2 SO_{2(g)} + 2 NO_{2(g)} \rightarrow 2 SO_{3(g)} + 2 NO_{(g)}$
$(ii)$ $2 NO_{(g)} + O_{2(g)} \rightarrow 2 NO_{2(g)}$
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Overall: $2 SO_{2(g)} + O_{2(g)} \rightarrow 2 SO_{3(g)}$
- A$NO_{2(g)}$
- B$NO_{(g)}$
- C$SO_{2(g)}$
- D$O_{2(g)}$
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Similar Questions
The reaction between $A$ and $B$ is first order with respect to $A$ and zero order with respect to $B$. Fill in the blanks in the following table:
Experiment $[A] / mol \, L^{-1}$ $[B] / mol \, L^{-1}$ Initial rate / $mol \, L^{-1} \, min^{-1}$ $I$ $0.1$ $0.1$ $2.0 \times 10^{-2}$ $II$ $-$ $0.2$ $4.0 \times 10^{-2}$ $III$ $0.4$ $0.4$ $-$ $IV$ $-$ $0.2$ $2.0 \times 10^{-2}$
| Experiment | $[A] / mol \, L^{-1}$ | $[B] / mol \, L^{-1}$ | Initial rate / $mol \, L^{-1} \, min^{-1}$ |
|---|---|---|---|
| $I$ | $0.1$ | $0.1$ | $2.0 \times 10^{-2}$ |
| $II$ | $-$ | $0.2$ | $4.0 \times 10^{-2}$ |
| $III$ | $0.4$ | $0.4$ | $-$ |
| $IV$ | $-$ | $0.2$ | $2.0 \times 10^{-2}$ |
Difficult
View SolutionThe mechanism of the reaction $2NO_{(g)} + Br_{2(g)} \rightarrow 2NOBr_{(g)}$ is given by:
$1) NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$ (fast)
$2) NOBr_{2(g)} + NO_{(g)} \rightarrow 2NOBr_{(g)}$ (slow)
If the second step is the rate-determining step,what is the order of the reaction with respect to $NO_{(g)}$?
$1) NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$ (fast)
$2) NOBr_{2(g)} + NO_{(g)} \rightarrow 2NOBr_{(g)}$ (slow)
If the second step is the rate-determining step,what is the order of the reaction with respect to $NO_{(g)}$?
Medium
View SolutionFor a reaction of order $n$,the unit of the rate constant is :
For a reaction $r = k[A][B]^2$,if the concentration of $A$ is doubled,the rate of reaction:
For the non-stoichiometric reaction $2A + B \rightarrow C + D,$ the following kinetic data were obtained in three separate experiments,all at $298 \, K.$
Initial Concentration $(A)$ Initial Concentration $(B)$ Initial rate of formation of $C$ $(mol \, L^{-1} \, s^{-1})$ $0.1 \, M$ $0.1 \, M$ $1.2 \times 10^{-3}$ $0.1 \, M$ $0.2 \, M$ $1.2 \times 10^{-3}$ $0.2 \, M$ $0.1 \, M$ $2.4 \times 10^{-3}$
The rate law for the formation of $C$ is:
| Initial Concentration $(A)$ | Initial Concentration $(B)$ | Initial rate of formation of $C$ $(mol \, L^{-1} \, s^{-1})$ |
| $0.1 \, M$ | $0.1 \, M$ | $1.2 \times 10^{-3}$ |
| $0.1 \, M$ | $0.2 \, M$ | $1.2 \times 10^{-3}$ |
| $0.2 \, M$ | $0.1 \, M$ | $2.4 \times 10^{-3}$ |
The rate law for the formation of $C$ is:
DifficultJEE MAIN 2014
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