Identify the correct set for the $[Co(NH_3)_6]^{3+}$ ion regarding the hybridization of $Co^{3+}$,type of complex,and the number of unpaired electrons in the complex ion,respectively.

  • A
    $d^2sp^3$,inner orbital complex,zero
  • B
    $sp^3d^2$,outer orbital complex,three
  • C
    $d^2sp^3$,inner orbital complex,two
  • D
    $sp^3d^2$,outer orbital complex,zero

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Which of the following complexes has $dsp^2$ hybridisation?

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Match List-$I$ with List-$II$:
List-$I$ List-$II$
$A. K_2[Ni(CN)_4]$ $I. sp^3$
$B. [Ni(CO)_4]$ $II. sp^3d^2$
$C. [Co(NH_3)_6]Cl_3$ $III. dsp^2$
$D. Na_3[CoF_6]$ $IV. d^2sp^3$

Choose the correct answer from the options given below:

$[NiCl_{4}]^{2-}$ is paramagnetic while $[Ni(CO)_{4}]$ is diamagnetic though both are tetrahedral. Why?

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. $[MnBr_4]^{2-}$ $I$. $d^2sp^3$ and diamagnetic
$B$. $[FeF_6]^{3-}$ $II$. $sp^3d^2$ and paramagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$ $III$. $sp^3$ and diamagnetic
$D$. $[Ni(CO)_4]$ $IV$. $sp^3$ and paramagnetic

Choose the correct answer from the options given below:

Point out the correct statements amongst the following.

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