Which of the following complexes has dsp^2 hy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$ ($3d^8$ configuration).$CN^-$ is a strong field ligand,which causes the pairing of electro

Vedclass · Accepted Answer

$[Ni(CN)_4]^{2-}$

Vedclass · Answer

(B) In $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$ ($3d^8$ configuration).$CN^-$ is a strong field ligand,which causes the pairing of electrons in the $3d$ orbitals.This leaves one $3d$ orbital,one $4s$ orbital,and two $4p$ orbitals vacant,which undergo $dsp^2$ hybridisation to form a square planar geometry.Conversely,$[Ni(CO)_4]$ and $[NiCl_4]^{2-}$ involve $sp^3$ hybridisation,resulting in a tetrahedral geometry.

Which of the following complexes has $dsp^2$ hybridisation?

Similar Questions

$K_3[CoF_6]$ is a high-spin complex. The hybridization state of $Co$ in this complex is .....................

Which of the following has $dsp^2$ hybridization?

Nickel $(Z = 28)$ combines with a uninegative monodentate ligand $X^{-}$ to form a paramagnetic complex $[NiX_4]^{-2}.$ The number of unpaired electron$(s)$ in the nickel and geometry of this complex ion are,respectively $:$

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

The complex ion $[Cu(NH_3)_4]^{2+}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module