Match List-I with List-II.

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(D) $(A) [MnBr_4]^{2-}$: $Mn^{2+}$ is $[Ar] 3d^5$. $Br^-$ is a weak field ligand,so it undergoes $sp^3$ hybridization and is paramagnetic.
$(B) [FeF_

Vedclass · Accepted Answer

$A-IV, B-II, C-I, D-III$

Vedclass · Answer

(D) $(A) [MnBr_4]^{2-}$: $Mn^{2+}$ is $[Ar] 3d^5$. $Br^-$ is a weak field ligand,so it undergoes $sp^3$ hybridization and is paramagnetic.
$(B) [FeF_6]^{3-}$: $Fe^{3+}$ is $[Ar] 3d^5$. $F^-$ is a weak field ligand,so it undergoes $sp^3d^2$ hybridization and is paramagnetic.
$(C) [Co(C_2O_4)_3]^{3-}$: $Co^{3+}$ is $[Ar] 3d^6$. $C_2O_4^{2-}$ is a strong field ligand,so it undergoes $d^2sp^3$ hybridization and is diamagnetic.
$(D) [Ni(CO)_4]$: $Ni^0$ is $[Ar] 3d^8 4s^2$. $CO$ is a strong field ligand,so it undergoes $sp^3$ hybridization and is diamagnetic.
Therefore,the correct matching is $A-IV, B-II, C-I, D-III$.

List-$I$	List-$II$
$A$. $[MnBr_4]^{2-}$	$I$. $d^2sp^3$ and diamagnetic
$B$. $[FeF_6]^{3-}$	$II$. $sp^3d^2$ and paramagnetic
$C$. $[Co(C_2O_4)_3]^{3-}$	$III$. $sp^3$ and diamagnetic
$D$. $[Ni(CO)_4]$	$IV$. $sp^3$ and paramagnetic

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