Identify product $B$ in the following reaction: $\text{Propanone}$ $\xrightarrow{\text{Ba(OH)}_2} A$ $\xrightarrow{\Delta, -\text{H}_2\text{O}} B$

An organic compound $x$ where the molar ratio of $C$,$O$,and $H$ are equal,on treatment with $50\% \ KOH$ under reflux followed by acidification produced $y$. The most likely structure of $y$ is: [Molar mass of $x$ is $58 \ g \ mol^{-1}$]

What is reactant $A$?

Formaldehyde when treated with $KOH$ gives methanol and potassium formate. The reaction is known as

Compound $A$ (molecular formula $C_3H_8O$) is treated with acidified potassium dichromate to form a product $B$ (molecular formula $C_3H_6O$). $B$ forms a shining silver mirror on warming with ammoniacal silver nitrate,and $B$ when treated with an aqueous solution of $NH_2NHCONH_2$ and sodium acetate gives a product $C$. Identify the structure of $C$.

Which of the following compounds will react with water?