An organic compound $x$ where the molar ratio of $C$,$O$,and $H$ are equal,on treatment with $50\% \ KOH$ under reflux followed by acidification produced $y$. The most likely structure of $y$ is: [Molar mass of $x$ is $58 \ g \ mol^{-1}$]

  • A
    $CH_{2} = CH - C(=O) - OH$
  • B
    $CH_{3} - CH = CH - CH = O$
  • C
    $HO - CH_{2} - COOH$
  • D
    $CH_{3} - C(=O) - OH$

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