Compound A (molecular formula C_3H_8O) is tre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) is $CH_3CH_2CH_2OH$ (propan$-1-$ol),which on oxidation with acidified $K_2Cr_2O_7$ gives $B$ ($CH_3CH_2CHO$,propanal).$B$ gives a positive Tollen'

Vedclass · Accepted Answer

$CH_3CH_2CH=NNHCONH_2$

Vedclass · Answer

(A) is $CH_3CH_2CH_2OH$ (propan$-1-$ol),which on oxidation with acidified $K_2Cr_2O_7$ gives $B$ ($CH_3CH_2CHO$,propanal).$B$ gives a positive Tollen's test (shining silver mirror),confirming it is an aldehyde.Reaction of propanal $(CH_3CH_2CHO)$ with semicarbazide $(NH_2NHCONH_2)$ in the presence of sodium acetate yields the semicarbazone product $C$.The reaction is: $CH_3CH_2CHO + NH_2NHCONH_2 \rightarrow CH_3CH_2CH=NNHCONH_2 + H_2O$.Therefore,the structure of $C$ is $CH_3CH_2CH=NNHCONH_2$.

Similar Questions

Which of the following reactions converts the carbonyl group of aldehydes and ketones to a methylene group on treatment with zinc amalgam and concentrated $HCl$?

Wolff-Kishner reduction reduces which of the following groups?

The major product $A$ is:

Consider the following reaction sequence:
$B \xleftarrow{NaBH_4} CH_2=CH-CHO \xrightarrow{H_2/Pt} A$
Identify $A$ and $B$.

The product of the above reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module