Identify a molecule having the highest number | vedclass

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(C) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of

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$ICl_3$

Vedclass · Answer

(C) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (monovalent atoms attached).$1$. For $NH_3$: $N$ is $5$,$V = 5$,$N = 3$. $	ext{Lone pairs} = \frac{1}{2} (5 - 3) = 1$.$2$. For $SF_4$: $S$ is $6$,$V = 6$,$N = 4$. $	ext{Lone pairs} = \frac{1}{2} (6 - 4) = 1$.$3$. For $ICl_3$: $I$ is $7$,$V = 7$,$N = 3$. $	ext{Lone pairs} = \frac{1}{2} (7 - 3) = 2$.$4$. For $PCl_3$: $P$ is $5$,$V = 5$,$N = 3$. $	ext{Lone pairs} = \frac{1}{2} (5 - 3) = 1$.Thus,$ICl_3$ has the highest number of lone pairs $(2)$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $XeF_4$	$I$. Square pyramidal
$B$. $ClF_3$	$II$. Pentagonal bipyramidal
$C$. $BrF_5$	$III$. Square planar
$D$. $IF_7$	$IV$. Bent $T$-shape

Identify a molecule having the highest number of lone pairs of electrons in the valence shell of the central atom.

Similar Questions

Which of the following molecules has trigonal planar geometry?

Match the following:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $XeF_4$ $I$. Square pyramidal

$B$. $ClF_3$ $II$. Pentagonal bipyramidal

$C$. $BrF_5$ $III$. Square planar

$D$. $IF_7$ $IV$. Bent $T$-shape

Which of the following molecules has a planar structure?

$H_2O$ is

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