What hybrid orbitals are present in the follo | vedclass

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(B) The hybridization of carbon atoms is determined by the number of sigma bonds and lone pairs attached to them.$1$. The terminal $CH_3$ groups are b

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$sp^2$ and $sp^3$

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(B) The hybridization of carbon atoms is determined by the number of sigma bonds and lone pairs attached to them.$1$. The terminal $CH_3$ groups are bonded to four atoms (three $H$ and one $C$),so they are $sp^3$ hybridized.$2$. The $CH_2$ group is bonded to four atoms (two $H$ and two $C$),so it is $sp^3$ hybridized.$3$. The $CH$ groups involved in the double bond are bonded to three atoms (one $H$ and two $C$),so they are $sp^2$ hybridized.Therefore,the compound contains $sp^2$ and $sp^3$ hybridized carbon atoms.Structure: $\mathop{CH_3}\limits_{sp^3} - \mathop{CH}\limits_{sp^2} = \mathop{CH}\limits_{sp^2} - \mathop{CH_2}\limits_{sp^3} - \mathop{CH_3}\limits_{sp^3}$

What hybrid orbitals are present in the following compound $H_3C - CH = CH - CH_2 - CH_3$?

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