Number of pure p- orbitals in the given molec | vedclass

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(A) The structure of $	ext{hexa-}1, 3-	ext{dien-}5-	ext{yne}$ is $CH_2=CH-CH=CH-C\equiv CH$.In this molecule,the carbon atoms involved in double bo

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The structure of $	ext{hexa-}1, 3-	ext{dien-}5-	ext{yne}$ is $CH_2=CH-CH=CH-C\equiv CH$.In this molecule,the carbon atoms involved in double bonds ($sp^2$ hybridized) each have one pure $p-$orbital.There are $4$ such carbon atoms $(C_1, C_2, C_3, C_4)$,contributing $4$ pure $p-$orbitals.The carbon atoms involved in the triple bond ($sp$ hybridized) each have two pure $p-$orbitals.There are $2$ such carbon atoms $(C_5, C_6)$,contributing $2 	imes 2 = 4$ pure $p-$orbitals.Total number of pure $p-$orbitals = $4 + 4 = 8$.

Number of pure $p-$ orbitals in the given molecule $\text{hexa-}1, 3-\text{dien-}5-\text{yne}$.

Similar Questions

The hybridisation of the negatively charged carbon atoms in $(1)$ and $(2)$ are:
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$(2)$ $H_2C^- - CHO - CH_3$

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$(iii)$ $CH_2=CH-CH=CH_2$
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