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(B) The starting material is $p$-nitrotoluene $(CH_3-C_6H_4-NO_2)$.$(i)$ Reduction of $-NO_2$ to $-NH_2$ gives $p$-toluidine $(CH_3-C_6H_4-NH_2)$.(ii)

Vedclass · Accepted Answer

$1$

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(B) The starting material is $p$-nitrotoluene $(CH_3-C_6H_4-NO_2)$.$(i)$ Reduction of $-NO_2$ to $-NH_2$ gives $p$-toluidine $(CH_3-C_6H_4-NH_2)$.(ii) Acetylation of the amino group with acetic anhydride gives $p$-methylacetanilide $(CH_3-C_6H_4-NHCOCH_3)$.(iii) Bromination occurs at the ortho position relative to the $-NHCOCH_3$ group,yielding $2$-bromo-$4$-methylacetanilide.(iv) Hydrolysis of the acetamido group gives $2$-bromo-$4$-methylaniline $(C_7H_8BrN)$.This product $(P)$ is $2$-bromo-$4$-methylaniline. Its molar mass is $(7 	imes 12) + (8 	imes 1) + 80 + 14 = 84 + 8 + 80 + 14 = 186 	ext{ g/mol}$.In Carius analysis,$1 	ext{ mole}$ of $P$ produces $1 	ext{ mole}$ of $	ext{AgBr}$.Moles of $P = 1.0 	ext{ g} / 186 	ext{ g/mol} \approx 0.005376 	ext{ mol}$.Moles of $	ext{AgBr} = 0.005376 	ext{ mol}$.Mass of $	ext{AgBr} = 0.005376 	imes (108 + 80) = 0.005376 	imes 188 \approx 1.01 	ext{ g}$.The nearest integer is $1$.

Similar Questions

What are $X$ and $Y$ respectively in the following set of reactions?

This reaction is an example of:

Predict the stereochemistry of the product when a $d$ and $l$-amine mixture reacts with an $l$-acid.

In a reaction of aniline,a coloured product $C$ was obtained as shown below:
$A$ $\xrightarrow{NaNO_2/HCl} B$ $\xrightarrow{N,N-dimethylaniline, \text{cold}} C$
The structure of $C$ would be:

How will you convert:
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$(iii)$ $Cl-(CH_2)_4-Cl$ into hexane-$1,6$-diamine?

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