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(D) 						$(i)$			$CH_3COCH_3$ $\xrightarrow{NaBH_4} CH_3CH(OH)CH_3$ $\xrightarrow{	ext{conc. } H_2SO_4, \Delta} CH_3CH=CH_2$							$(ii)$			$C_6H_5C

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(D) 						$(i)$			$CH_3COCH_3$ $\xrightarrow{NaBH_4} CH_3CH(OH)CH_3$ $\xrightarrow{	ext{conc. } H_2SO_4, \Delta} CH_3CH=CH_2$							$(ii)$			$C_6H_5COOH$ $\xrightarrow{SOCl_2} C_6H_5COCl$ $\xrightarrow{H_2/Pd-BaSO_4} C_6H_5CHO$							$(iii)$			$CH_3CH_2OH$ $\xrightarrow{PCC} CH_3CHO$ $\xrightarrow{	ext{dil. } NaOH} CH_3CH(OH)CH_2CHO$							$(iv)$			$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} C_6H_5COCH_3$ $\xrightarrow{	ext{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COCH_3$							$(v)$			$C_6H_5CHO$ $\xrightarrow[2. H_3O^+]{1. C_6H_5MgBr} C_6H_5CH(OH)C_6H_5$ $\xrightarrow{Na_2Cr_2O_7/H_2SO_4} C_6H_5COC_6H_5$							$(vi)$			$C_6H_5Br$ $\xrightarrow{Mg/	ext{ether}} C_6H_5MgBr$ $\xrightarrow[2. H_3O^+]{1. CH_3CHO} C_6H_5CH(OH)CH_3$							$(vii)$			$C_6H_5CHO + CH_3CHO$ $\xrightarrow{	ext{dil. } NaOH} C_6H_5CH=CHCHO$ $\xrightarrow{H_2/Ni} C_6H_5CH_2CH_2CH_2OH$							$(viii)$			$C_6H_5CHO$ $\xrightarrow{HCN} C_6H_5CH(OH)CN$ $\xrightarrow{H_3O^+} C_6H_5CH(OH)COOH$							$(ix)$			$C_6H_5COOH$ $\xrightarrow{	ext{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COOH$ $\xrightarrow{B_2H_6} m-NO_2-C_6H_4CH_2OH$

Similar Questions

Which of the following tetracarboxylic acids forms a di-anhydride upon heating?

Product $(A)$ of the reaction is:

The final product $(III)$ obtained in the reaction sequence is:
$CH_3-CH_2-COOH$ $\xrightarrow{PCl_3} I$ $\xrightarrow{C_6H_6/AlCl_3} II$ $\xrightarrow{NH_2-NH_2/\text{base/heat}} III$

The major product in the following reaction is

The following transformation can be carried out in three steps. The reagents required for these three steps in their correct order are:

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$(i)$	$CH_3COCH_3$ $\xrightarrow{NaBH_4} CH_3CH(OH)CH_3$ $\xrightarrow{\text{conc. } H_2SO_4, \Delta} CH_3CH=CH_2$
$(ii)$	$C_6H_5COOH$ $\xrightarrow{SOCl_2} C_6H_5COCl$ $\xrightarrow{H_2/Pd-BaSO_4} C_6H_5CHO$
$(iii)$	$CH_3CH_2OH$ $\xrightarrow{PCC} CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} CH_3CH(OH)CH_2CHO$
$(iv)$	$C_6H_6$ $\xrightarrow{CH_3COCl/AlCl_3} C_6H_5COCH_3$ $\xrightarrow{\text{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COCH_3$
$(v)$	$C_6H_5CHO$ $\xrightarrow[2. H_3O^+]{1. C_6H_5MgBr} C_6H_5CH(OH)C_6H_5$ $\xrightarrow{Na_2Cr_2O_7/H_2SO_4} C_6H_5COC_6H_5$
$(vi)$	$C_6H_5Br$ $\xrightarrow{Mg/\text{ether}} C_6H_5MgBr$ $\xrightarrow[2. H_3O^+]{1. CH_3CHO} C_6H_5CH(OH)CH_3$
$(vii)$	$C_6H_5CHO + CH_3CHO$ $\xrightarrow{\text{dil. } NaOH} C_6H_5CH=CHCHO$ $\xrightarrow{H_2/Ni} C_6H_5CH_2CH_2CH_2OH$
$(viii)$	$C_6H_5CHO$ $\xrightarrow{HCN} C_6H_5CH(OH)CN$ $\xrightarrow{H_3O^+} C_6H_5CH(OH)COOH$
$(ix)$	$C_6H_5COOH$ $\xrightarrow{\text{conc. } HNO_3/H_2SO_4} m-NO_2-C_6H_4COOH$ $\xrightarrow{B_2H_6} m-NO_2-C_6H_4CH_2OH$