Which of the following tetracarboxylic acids | vedclass

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a

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Both $(a)$ and $(b)$

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(D) Heating $1,2-$dicarboxylic acids leads to the formation of cyclic anhydrides by the loss of a water molecule. For a tetracarboxylic acid to form a di-anhydride,it must have two pairs of adjacent carboxylic acid groups. In benzene$-1,2,3,4-$tetracarboxylic acid,there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $3,4$),allowing for the formation of a di-anhydride. In benzene$-1,2,4,5-$tetracarboxylic acid (pyromellitic acid),there are two pairs of adjacent $-COOH$ groups (at positions $1,2$ and $4,5$),which also allows for the formation of a di-anhydride. Therefore,both compounds can form di-anhydrides upon heating.

Which of the following tetracarboxylic acids forms a di-anhydride upon heating?

Similar Questions

The above conversion can be done by:

The general formula for monocarboxylic acids is

What is the final product $(B)$ of this sequence?

$(i) \ F_3CCOOH$
$(ii) \ CH_3COOH$
$(iii) \ C_6H_5COOH$
$(iv) \ CH_3CH_2COOH$
Correct order of $pK_a$ value is:

The product $(C)$ of the given reaction sequence is:

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